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Commutable Islands

Logical Breakdown

  • [ ] Subproblem Identification:
  • [ ] Optimal Substructure:
  • [ ] Constraint Handling: (e.g., Modulo \(10^9 + 7\))
  • [ ] Optimization: (Matrix Exponentiation if 'A' is huge)

Mathematical Rigor

State Definition

Let \(dp[i]\) be the state for the \(i\)-th subproblem.

Recurrence Relation

\[ dp[i] = ... \]

Visualization

graph TD A["Current State"] --> B["Previous State 1"] A --> C["Previous State 2"]

Complexity Analysis

Approach Time Complexity Space Complexity
Iterative DP \(O(N)\) \(O(1)\)

Code Reference

package com.dsa.graphs;

/* * ============================================================================================ * PROBLEM: Commutable Islands (Minimum Spanning Tree) * ============================================================================================ * * --------------------- * 1. Problem Description * --------------------- * Given A islands and M bridges with associated costs. Find the minimum total cost * to connect all islands such that every island is reachable from every other island. * This is the classic definition of finding the Minimum Spanning Tree (MST) of a graph. * * --------------------- * 2. Logical Breakdown & Mathematical Formulation * --------------------- * We use Kruskal's Algorithm to solve this, which greedily picks the cheapest edges. * * Step 1: Sorting * Sort all M bridges in non-descending order based on their cost. * * Step 2: Disjoint Set Union (DSU) Initialization * Initialize a DSU structure for A nodes. Each node is initially its own parent * (its own component). * * Step 3: Edge Selection (Greedy) * Iterate through the sorted bridges. For each bridge connecting islands u and v: * 1. Find the absolute root of u and v using the find operation. * 2. If find(u) != find(v): * - The islands are currently in different components. * - Adding this bridge will NOT form a cycle. * - Add the bridge's cost to the total MST cost. * - Perform union(u, v) to merge the two components. * 3. If find(u) == find(v), skip the bridge to avoid a cycle. * * Step 4: Termination * Stop once we have successfully added (A - 1) bridges or processed all edges. * * --------------------- * 3. Constraints & Complexity Analysis * --------------------- * Constraints: * 1 <= A, M <= 6 * 10^4 * 1 <= Cost <= 10^3 * * Time Complexity: * O(M log M + M α(A)) * - Sorting edges: O(M log M). * - DSU operations: O(M α(A)), where α is the inverse Ackermann function (near-constant). * * Space Complexity: * O(A + M) - To store the parent/rank arrays for DSU and the edge list. * * ============================================================================================ / public class CommutableIslands { public int solve(int A, int[][] b3) { // TODO: Implement solution return 0; } }